solved new crackme

CM2_3/solve.md

@@ -0,0 +1,69 @@
+根据name算SN
+
+先来一组可用的name&SN:
+
+```
+Name: chenx221
+SN: 14wact6
+```
+
+思路：
+
+```
+SN: CRC32(MD5("vhly[FR]" + name))结果的36进制形式
+
+MessageDigest var6 = MessageDigest.getInstance(I.I(47)); // MD5
+var6.update(I.I(51).getBytes()); // vhly[FR]
+这两处字符串被藏在了I.gif里，I.gif处理方法和该crackme上一代相同
+使用上次准备的读取器可以获取这些字符串：
+ExiTChECk"Name length must more than 3 charsMD5vhly[FR]Serial is WrongSerial is Right! YOuR OK
+```
+
+细节：
+
+```java
+String var3 = addActionListener.getText(); // Name
+String var4 = digest.getText(); // SN
+if (var3 == null) {
+    return;
+}
+
+if (var4 == null) {
+    return;
+}
+
+if (var3.length() <= 3) {
+    JOptionPane.showMessageDialog(this, I.I(12));
+    return;
+}
+
+byte[] var5 = null;
+
+try {
+    MessageDigest var6 = MessageDigest.getInstance(I.I(47)); // MD5
+    var6.update(I.I(51).getBytes()); // vhly[FR]
+    var6.update(var3.getBytes()); // Name
+    var5 = var6.digest(); // Convert vhly[FR]+Name to MD5
+} catch (Exception var12) {
+}
+
+CRC32 var13 = new CRC32();
+var13.update(var5);
+long var7 = var13.getValue();
+long var9 = Long.parseLong(var4, 36); // 36进制
+boolean var11 = false;
+if (var7 / var9 == 1L) {
+    var11 = true;
+} else {
+    var11 = false;
+}
+
+if (!var11) {
+    JOptionPane.showMessageDialog(this, I.I(60));
+    return;
+}
+
+JOptionPane.showMessageDialog(this, I.I(76));
+return;
+```
+

CM2_3/vhly.nfo

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+name: Java CrackMe #2
+author: vhly[FR]
+email: vhly@163.com
+date: 2006/01/13