solved new crackme

checkmeproject_scrb/keygen.py

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+name = "chenx221"
+total_ascii = sum(ord(char) for char in name)
+serial = total_ascii * 2003 * len(name)
+print(serial)

checkmeproject_scrb/readme.txt

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+'The Checkme Project'
+
+This small crackme was intensionally coded for a friend of mine who wanted to have an easy exercise target for SMARTCHECK. 
+As it turned out i think it is rather educational, so i decided to put it out in public ;-)
+
+The crackme consists of 3 parts:
+
+1st part: 
+Hardcoded serial. Basic checking, so just find the password.
+
+2nd part: 
+Little more difficult, but still hardcoded. Same rule, just find the serial.
+
+3rd part:
+Easy name/serial check. Find a valid serial for your name, and explain how the algorythme works. If you feel like it, convert it into a keygen, as it is very easy.
+
+If you finish all the parts, you should be able to understand the basics of smartcheck.
+
+The only rule:
+
+-> ONLY use Smartcheck. No other tools allowed!
+
+Greetings to _RiPTiDE_ , _PUSHER_ and all who share this interest!
+Happy checking!!
+
+Send solutions, or whatever to:
+
+scarabee_5@hotmail.com
+
+
+

checkmeproject_scrb/solve.md

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+用nmp的smartcheck
+
+Part1 serial:
+
+```
+SsCcAaRrAaBbEeEe
+```
+
+Part2 serial:
+
+```
+SCRB2003
+```
+
+```
+Data:   SC0B3R20
+Index:  12748356
+Serial: SCRB2003
+```
+
+Part3 serial:
+
+```
+示例serial:
+chenx221
+10944392
+```
+
+```python
+name = "22"
+total_ascii = sum(ord(char) for char in name)
+serial = total_ascii * 2003 * len(name)
+print(serial)
+```